3/4y=1/2y^2

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Solution for 3/4y=1/2y^2 equation: 


y in (-oo:+oo)

(3/4)*y = (1/2)*y^2 // - (1/2)*y^2

(3/4)*y-((1/2)*y^2) = 0

(-1/2)*y^2+(3/4)*y = 0

3/4*y-1/2*y^2 = 0

DELTA = (3/4)^2-(-1/2*0*4)

DELTA = 9/16

DELTA > 0

y = ((9/16)^(1/2)-3/4)/(-1/2*2) or y = (-(9/16)^(1/2)-3/4)/(-1/2*2)

y = 0 or y = 3/2

y in { 0, 3/2 }

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